Determination of Unknown Salt Experiment

Determination of Unknown Salt ExperimentSiar AziziIntroductionCold imparts or medical glacial packs are do and utilise in a variety of incompatible ways. Cold packs are typic bothy used in regards of medical treatment. Many athletes used cold-blooded packs to heal from any injuries. Furthermore, cold packs are used to keep medications cool for a reachn period, such(prenominal) medications include vaccinations. Cold packs contain a liquid indoors, in near cases its pee. In addition the piss is mixed with a flavor, which bothows the cold pack to stay cool. The mixture that occurs between the flavour and the water provokes an endothermal reaction, which sum that warmness is absorbed. delinquent to the warming absorption, the temperature of the solution go forth decrease substantially.The cold pack test research testing groundoratory allowed us, the students, to apply theories learned in split up to demonstrable real life experiments such experiments prepare us f or future day tasks the will be rank forth to denounce up. Our chief(prenominal) trajectory by dint of this assignment was to picture what our foreign common table sodium chloride was, through experimental analysis. The main purpose of this lab was for us to cycle back what the given dark table table salt is. For this experiment, my group and I were given mysterious salt 7. Information accept before starting the lab, were the materials undeniable, background information on the math leaded to pay off the unknown(s). In addition, other background founts before starting the experiment included having previous knowledge of chemical formulas, understanding concepts learned passim class and how a calorimetry works. Furthermore in distinguish to mend how to substitute the lab, we needed information upon how to properly keep the temperature of the water from decreasing or increasing, and this required that we needed to know what an insulator is and how to use it.T o base a conclusion on what the unknown variables are, we needed to determine how to start and fatten this experiment. To macrocosm with, we completed this activity by fetching twain of the trey form bubbles loving cups and placing them into each other. The foam cup inside the other cup will hold our water, while the other acts as an insulator, to pr neverthelesst heat from escaping. Secondly, we used a graduated piston chamber and calculated 25.0-ml of water into it and put the water into the cup. by and by that we taper the third cup, over the other both (acts like a cover) and put the thermometer through the top of the cup (This helps us determine the temperature of the water). Lastly, we measured the 3.0grams of our unknown salt and placed that into the water, letting it disregard, and measured the temperature.The theories that needed to be readn into account for to help complete the lab, includes determine the heat capacity, q=mcT. Other theories that we will also n eed to take into account for include, determine heat content, determine the change in temperature, and determining the circumstances birth. In put together to determine the enthalpy, the equivalence needed to be used is H=-q. The equation used to determine change in temperature and contri merelyion yield are, T= T1 T2 and percentage geological fault= speculative yield-Actual yield x100.TheoreticalAs you read on, every equation will be examined and explained on what they mean and how they will be used.Brain, Marshall , and Sara Elliot. How Refrigerators Work.HowStuffWorks. N.p., n.d. Web. 13 Apr. 2014. MaterialsThe materials required in order completing the lab included goggles/eye habiliment this will help hold any type of harmful substances that we worked with from negatively charged your eyes. Three Styrofoam cups, the cups helps make an insulator and create the calorimeter. The thermometer was required in order to determine the temperature of both the water and the un known salt. A weighing boat was also another(prenominal) outset of material needed, in order to place 3.0grams of our salt. In addition, a scoopula and a scale were needed to help us determine the exact measurements of the unknown salt needed. Water was required to fragmentize our salt into and measure the temperature of. A 100ml graduated cylinder was used to determine the accurate quantity of water required. Our unknown salt was another line of descent of material given by our teacher, and this allowed us to complete the experiment. Other materials needed in order to complete the lab included paper towels. bitIn order to determine what our unknown salt is, we needed to make a guideline of the steps required to determine it. The procedure of our lab isGather all equipment/ materials to start procedure.Weigh the weighing boat, record the weight. gear up 3.0 grams of our unknown salt 7Take two of the three foam cups and place them within each other to create an insulator from preventing heat to escape or cold air from entering.Take the 100-mL graduated cylinder and measure 25.0mL of water.Take the 25mL of water and place it in the two foam cupsCut the third Styrofoam cup to fit the top of the first two cups.Make a hole, place thermometer in the calorimeterRead the temperature of water record it.Remove thermometer, add 3.0grams of unknown salt into the calorimeter.Let the salt dissolve and determine the temperature, by placing the thermometer through the top of the third cup. sooner beat the temperature, shake the cup to insure the unknown salt reacted/ dissolved completely. secure the temperature and record tops.Dispose of waste, clean the equipment and restart for the remaining two trials.Observations and ResultsBefore beginning the calculations for the lab, we need to determine what possible equation we will brace to use.EquationsT= T2 T1The equation above is the change in temperature, represented by delta (), which is the second temperature record ed subtracted by the first temperature recorded (T2 T1).Q=mcTThe equation above allows us to determine the q, which is the quantity of heat bump offred, which equals the lot (m), multiplied by the specific heat capacity (c), and multiplied by the change in temperature (T=T2 T1 ).H=-qThe equation above allows us to solve for the H system. Once we determined the quantity of heat transferred, by using the equation q=mcT, we can determine delta h by either replacing the q with mcT, or place the result of q in the equation.Average Enthalpy= lede 1+Trail 2+Trail 33The equation above gives us the average enthalpy for the number of trails that was conducted by our group. We add up all the Enthalpy of all trials and divide it by 3, to give the average.Percent erroneousness= Theoretical yield-Actual yield x100TheoreticalThis equation allows us to determine the percentage error of our results. After calculating for our enthalpy, we can take the theoretical yield, found on rogue 347, tab le 1 in our textbook, we can subtract is by the genuine yield. After determining the hold dear of that, we divide it by the theoretical value and multiply it all by 100%.With the recording of all our info obtained from doing the experiment, we were able to form a chart for all three procedures and mathematically determine what the unknown salt was.Weighing Boat=1.81 GramsTemperature of water and unknown salt obtained from three trailsTable 1 Temperature results and Change in temperature of water through three trails. From this chart above, we can see that we completed three trails to determine the exact value of the unknown salt, and to determine what the unknown salt is. In addition, we recorded our temperatures of the water before the salt was added (T1) and after the salt was added (T2). From that point we calculated the change in the temperature for each trail, with the equation, H=T2 T1. affectionateness capacity and enthalpy of unknown salt for three trialsTable 2 Enthalpy and heat capacity of unknown salt 7 for three trials. The chart above shows the heat capacity and enthalpy of the unknown salt from three different tests conducted. We determined the heat capacity using the equation q=mcT and the enthalpy using mH=q. The calculations for determine the results are shown belowCalculationsNote 1mL is 1 gram. (M=dV, mass= density (1.00grams/mL) x volume (mL))Trail 1Q=mcT mH=-(q)Q= (25g) (4.18J/goC) (-8oC) (3.00g) H=-(-0.836KJ)Q= -836J H=0.836KJ/3.00gH=0.279KJ/gTrail 2Q=mcT mH=-(q)Q= (25g) (4.18J/goC) (-7oC) (3.00g) H=-(-0.7315KJ)Q= -731.5J H=0.7315JK/3.00gQ= -0.7315KJ H=0.2438KJ/gTrail 3Q=mcTmH=-(q)Q= (25g) (4.18J/goC) (-7oC) (3.00g) H=-(-0.7315KJ)Q=-731.5J H=0.7315KJ/3.00gQ=-0.7315KJ H=0.2438KJ/gAverage EnthalpyAvg Enthalpy= Trail 1+ Trail 2+ Trail 33 Avg Enthalpy= (0.279KJ/g) (0.2438KJ/g) (0.2438KJ/g)3Avg Enthalpy= 0.256KJ/gAfter determining our average enthalpy, we can determine what increase it is. Going into our textbook, onto page 347 and taking a look at table 1, we are given a list of compounds. The nearest compound our enthalpy is at is ammonium chloride. Ammonium chloride has an enthalpy of 0.277kj/g and we got an enthalpy of 0.256kj/g. using our knowledge based on rounding, we rounded up and made a conclusion stating that our compound was in situation ammonium chloride. helping YieldPercent error= Theoretical yield-Actual yield x100TheoreticalPercent error= 0.277KJ/g 0.256KJ/gx1000.277KJ/gPercent error= 7.58%Therefore, the percentage error of our results was 7.58%DiscussionThroughout the cold pack experiment not all our results were accurate. Our results werent as accurate because we stumbled upon some errors while completing the lab. iodin error that we en heel countered while completing this experiment and one that had an impact on our net results was the way our calorimeter was created. Through the experiment we were to assume that the calorimeter would create an isolated and insulated system, but in truth it didnt. As we proceeded through the experiment of place the water into our calorimeter, at that place was a possible moment when there was a transfer of heat in between the Styrofoam cups and the solution, in our case unknown salt 7. The stage when there whitethorn pass been a transfer of heat, was not taken into account and this could of turn over caused an increase or a decrease in the temperature of our solution. As we already know that the reaction was endothermic and since its endothermic the solution absorbed the heat, from the cups and reaction. Such an error would cause a change in the temperatures of our solution to either increase or decrease. The result of this error had a medium impact on our final results. This was a medium impact because it not only affected our solution, but also the measurements we took. Resolutions to possibly prevent this error from occurring includes, taking account that the temperature whitethorn increase or decrease due to that fact it isnt a n actual isolated system. Another solution can include using different materials that would insulate the solution better.Our second source of error was taking the measurements of the water and measuring the accurate temperature of the water. When taking the measurements of the temperature of both the water and solution, there could encounter been an error from what we saw and what we wrote. Furthermore, since we dont know whether the thermometer was actually inside the water, it could realize not been touching it which in turn gave us the hurt results. An example could include is when taking the temperature of the water, the thermometer could attain read 22oC and we could have seen it as 23oC or24oC. The result of this error had a medium effect on our selective information and due to this effect, our enthalpy wasnt as accurate, and didnt exactly check over the ones in the textbook. When measuring the amount of water required dispensing in the calorimeter we need to use a gradua ted cylinder for accurate measurements. The cylinder was to give us the accurate measurement of whether we had exactly 25ml of water or not. The error in this measurement was for us to check with if it was exactly 25ml, and this may have resulted in either something less than 25ml or more than 25ml. The impact the source of error had on our final result was medium. The impact was medium because even though it did affect our final results, it didnt affect it by a lot. It hadnt affected our results by a large quantity because the struggle between the solution we were supposed to get and the one we had, had a teeny-weeny margin of differences.The last source of error, that we hadnt taken account for passim the process of completing the experimental lab, may have had an impact on our final results. This error that affected our results was the fact that our unknown salt 7, was undetermined to air for a periodic time. collectable to a fact that the salt was exposed to air, it may hav e resulted in some of the salt reacting with the atmosphere. Due to this error, our results could have been incorrect because when massing the 3.0 grams, it could have reacted with the atmosphere, giving us 0.10 off, such as 2.90grams. This may not affect the results by a lot, but there would still be an effect on it. Another example of our results being affected by this includes that since some of our unknown salt reacted, when we measured the temperature it could have actually been either lower or higher than what we actually expected. For example, if the salt wasnt exposed to the atmosphere we could have got a temperature of 18oC, but preferably due to the fact it was exposed we got 20oC. The affect this had on our results and solution is a medium result. This is a medium result because if some of the unknown salt reacted, it would have been in such a small quantity, that it wouldnt have a large effect on our results. Possible solutions from stopping this fuss from occurring in cludes, either keeping the salt in an isolated room, put a tad more of the unknown salt in the water, just to counter act for the ones that reacted.In the mixed of completing the lab, we stumbled upon a mistake with determining the unknown salt. The mistake had an impact on final answer and wasnt taken into account that it may possible have an effect on our final solution. The mistake that may have been encountered includes that our unknown source of salt, when added into the water, may have not dissolved properly. This resulted in the reaction not taking place to dissolve the entire product, which may have affected the temperature that was measured. Due to the fact that the salt wasnt dissolved and it didnt participate in the reaction, the temperature we may have taken could have been only the waters temperature. This source of error had a large effect on our solution because we had no way of determining whether it dissolved or not, without tampering the solution. Furthermore, due to the fact of the error, we may have been given the wrong temperature of the solution that in turn gave us the incorrect results for the enthalpy. In accordance, not only will we have been given the incorrect enthalpy, but the results were affected as well. In order to prevent this source of error from occurring again, what I could do is, while the unknown salt is in the water, I could stir it to dissolve properly another method can include is to shake the calorimeter to dissolve the salt. When shaking it, I would hold it from the top to prevent heat transfer from my hand and the water. draw 1 From the diagram we can see the calorimeter being constructed and the final result is over on the right. I would hold the middle of the calorimeter and spin it close to to better dissolve the unknown salt. DoChem 095 passion of dissolver of Magnesium.DoChem 095 Heat of Solution of Magnesium. N.p., n.d. Web. 10 Apr. 2014. ConclusionIn conclusion, this experiment allowed us, the students, to use theories learned in class to real life applications, or real life applications that we will soon encounter. The lab better prepared us for what may be expected in the future, and allowed us to determine different factors that affected our results in more than one possible way. The cold pack experiment lab that was conducted by my group and I, had resulted in us facing errors such as measurement errors, errors including the calorimeter and errors including our unknown salt. These errors were recorded and explained to better help us prevent it from occurring again. By following the correct procedure and having the correct materials required, we were able to determine the final enthalpy. That allowed us to determine what our unknown salt was, which was ammonium chloride.BibliographyDoChem 095 Heat of Solution of Magnesium.DoChem 095 Heat of Solution of Magnesium. N.P., n.d. Web. 10 Apr. 2014. Brain, Marshall , and Sara Elliot. How Refrigerators Work.HowStuffWorks. N.p., n.d. Web. 13 Apr. 2014. Kessel, Hans Van. The Bohr nuclear Theory.Nelson Chemistry 12. Toronto Thomson Nelson, 2003. 174-76. 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